One Molecule of Acetaminophen
C8H9NO2; Green- Hyrdrogen, Red- Carbon, Turqois- Oxygen, Purple- Nitrogen, - Single Bond, = Double Bond, : Unshared Electron Pair, and --|--> Shows Negativity
Sunday, February 27, 2011
Acetaminophen And It's Polarity
The chemical formula for acetaminophen is C8H9NO2. Because of the variation of electronegativity, the unshared electron pairs, and the lack of "lines of symmetry", acetaminophen is a polar molecule. First, the electronegativity, demonstrated by the arrows, is a factor in determining polarity. For example, hydrogen has an electronegativity value of 2.2 and oxygen has an electronegativity value of 3.5. Therefore, the hydrogen's electron will tend to get closer to oxygen, making the oxygen atom more negative. The unshared electron pairs also factor into negativity because the more unshared electron pairs an atom has, the more negatively charged it is. Thirdly, for a molecule to be nonpolar its must have 2 or more lines of symmetry. Since acetaminophen has no lines of symmetry, it must be polar. The more negative side of this molecule is the side with the nitrogen atom (purple) and the oxygen atom (turquois) because those two atoms have high electronegatvity and more unshared pairs. The side with the carbon chain, therefore, is the more positive side. 
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Rebecca, you're blog is very sophisticated and very organized. And the drawing of your molecule is absolutely superb. It would have been nice to know the angle measures, but your drawing skills make up for that. And you definitely knew what you were talking about when you were describing the polarity of the molecule as well as its intermolecular forces. I really like how you gave an indepth account for each. Lastly, you had me sold on your ad, I really didn't know that acetaminophen was in Tylenonl, so every time I get a headache, I'll definitely by some from you!
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molecule
polarity
intermolecular forces
ad
Rebecca, I love this. I really like the picture of the molecule since it's obvious that you really took your time on it and the bond angles and arrows are correct. I also really liked the ad! It was informative and made it very clear that you'd done your research.
ReplyDeleteThanks for taking the time to discuss this, I feel strongly about it and love learning more on this topic. If possible, as you gain expertise, would you mind updating your blog
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This has greatly helped with my chemistry coursework. Thank you very much!
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